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p / pt = [1 + M^2 * (gam-1)/2]^-[gam/(gam-1)] It's not that hard

p / pt = [1 + M^2 * (gam-1)/2]^-[gam/(gam-1)] It's not that hard - p / pt = [1 + M^2 * (gam-1)/2]^-[gam/(gam-1)] It's not that hard Ph.D Pup

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my research has turned up nothing. how could the ball be in his hand when he clearly threw it?

my research has turned up nothing. how could the ball be in his hand when he clearly threw it?

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103,639 shares

Ph.D Pup

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meh

Well, according to my research Dogs rule and cats drool

Well, according to my research Dogs rule
and cats drool

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48,405 shares

Ph.D Pup

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meh

I've done immense amounts of research and i think I have reached a conclusion: I don't know how to read

I've done immense amounts of research and i think I have reached a conclusion: I don't know how to read

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491 shares

Ph.D Pup

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It says here that a bitch... is the female of the species.

It says here that a bitch... is the female of the species.

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223 shares

Ph.D Pup

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meh

p / pt = [1 + M^2 * (gam-1)/2]^-[gam/(gam-1)] It's not that hard

p / pt = [1 + M^2 * (gam-1)/2]^-[gam/(gam-1)] It's not that hard

add your own caption

118 shares

Ph.D Pup

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meh

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